24x^2-22x+5=0

Solution for 24x^2-22x+5=0 equation:

24x^2-22x+5=0

a = 24; b = -22; c = +5;
Δ = b2-4ac
Δ = -222-4·24·5
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2}{2*24}=\frac{20}{48}
=5/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2}{2*24}=\frac{24}{48}
=1/2
$